[libre-riscv-dev] buffered pipeline

Luke Kenneth Casson Leighton lkcl at lkcl.net
Wed Mar 13 07:48:39 GMT 2019

On Wed, Mar 13, 2019 at 4:21 AM Luke Kenneth Casson Leighton <lkcl at lkcl.net>

yes we don't care what the output is: i can see that o_n_stb has gone LOW,
> so the output 0x21 is known to be invalid: i'd just prefer that the output
> not be computed at all if the input's not valid, to save power.
> would it be as simple as setting the combinatorial result computation on
> the condition that i_p_stb is HIGH?
         # store result of processing in combinatorial temporary
        result = Signal(16)
        with m.If(self.i_p_stb): # input is valid: process it
            m.d.comb += result.eq(self.process(self.i_data))
        with m.If(o_p_busyn): # not stalled
            m.d.sync += self.r_data.eq(result)

seems to do the trick: the output is now "0x0000" when o_n_stb goes LOW.

so, dan, in... verilog it would be....

if (i_stb) then
   result = logic(i_data);

then replacing all occurrences of "logic(i_data)" with "result", including

always @(posedge i_clk)
if (!o_busy)
r_data <= logic(i_data);

would now be:

always @(posedge i_clk)
if (!o_busy)
r_data <= result;

so that's no longer about stopping two sets of logic() block from being
created, it's about ensuring that the processing does not occur
unnecessarily (i.e. only when input is valid).

what do you think?


More information about the libre-riscv-dev mailing list