[libre-riscv-dev] [Bug 44] IEEE754 FPU inverse-sqrt

Hendrik Boom hendrik at topoi.pooq.com
Wed May 1 16:21:17 BST 2019


On Wed, May 01, 2019 at 05:40:57AM +0000, bugzilla-daemon at libre-riscv.org wrote:
> http://bugs.libre-riscv.org/show_bug.cgi?id=44
> 
> --- Comment #7 from Luke Kenneth Casson Leighton <lkcl at lkcl.net> ---
> (In reply to Jacob Lifshay from comment #6)
> > (In reply to Luke Kenneth Casson Leighton from comment #4)
> > > different approach:
> > > 
> > > https://rei.iteso.mx/bitstream/handle/11117/5844/Design+and+Implementation+of+Reciprocal+Square+Root+Units+on+Digital+ASIC+Technology+For+Low+Power+Embedded+Applications.pdf
> > there was a server error when I tried to access this
> > 
> > > https://github.com/tomverbeure/math/blob/master/src/main/scala/math/FpxxRSqrt.scala
> > 
> > as far as I can tell, this is only a lookup table.
> > 
> > > both these, as best i can tell, use a polynomial lookup table which requires
> > > only 1 iteration of newton-raphson to give full accuracy.
> > 
> > I think it would be wise to avoid newton-raphson since it needs several
> > multiplications and will occupy the multiplier for quite a few cycles.
> 
> The fixed rsqrt algorithm i saw was able to do the mult in a single cycle,
> however it may have been a smaller mantissa.
> 
> The algorithm you found, I really like it, only the description is really
> obtuse. Assuming we can do a 4 radix version, 2 of those can be combinatorially
> chained to give 8bit per cycle, and for FP32 that gives only around a 5 stage
> pipeline with basic single-shift, add and MUX blocks.
> 
> What is the sort of performance actually needed? Is this critical for certain
> circumstances?

Distance calculations are common in 3D geometry.
Square roots are involved using the Pythagorean theorem.
It has become traditional to try to avoid using square roots because they
are expensive and to find replacement algorithms that do not involve
distances.

Square root ought to be about as slow as long division at worst.

-- hendrik



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